Any of the three matches can have three **outcomes**. So by fundamental principle of counting, total number of **outcomes** are (like WWW, WLD, DLL, LDW etc.) 3*3*3=27.

Also, how many **possible** outcomes are there of 5 football **matches**? If only considering wins/losses, and ignoring the possibility of cancellation or forfeiture or other similar non-results, each match can be a win, loss, or tie from the perspective of each team. So, 3 **outcomes** per match, and 5 matches means there are 3^5 combinations, or 243.

In this regard, how **many** possible outcomes are there of 8 **football** **matches**? Example: 8 games with 2 eventualities (victory, defeat) represent a total of 28=256 2 8 = 256 combinations.

Furthermore, how many combinations of 3 games are there? Again, regardless of the outcome of the first two games there are two **possible** outcomes for the third game. Thus there are 2 × 2 × 2 = 23 = 8 possible outcomes if there are three games. This argument shows you how to determine the number of possibilities for any number of games.

Amazingly, how **many** 4 team combinations are there? You multiply these choices together to get your result: 4 x 3 x 2 (x 1) = 24. Combinations and permutations are often confused by students – they are related, but they mean different things and can lead to totally different interpretations of situations and questions.

## How many combinations of 4 items are there?

I.e. there are 4 objects, so the total number of possible combinations that they can be arranged in is 4! = 4 x 3 x 2 x 1 = 24.

## How many possible outcomes are there of 10 football matches?

so there are 2 possible outcomes. Thus, as you noted above there are possible outcomes. Thus there are 2 times 2 times 2 = 2^3 = 8 possible outcomes. Continuing in this way there are 2^{10} = 1024 possible outcomes for a 10 game situation.

## How many outcomes are there in 10 football matches?

By induction, each new game increases the number of potential outcomes by a factor of three. So for ten games, it is 310, which is about 59,000.

## How many outcomes are there in 17 football matches?

And the total different possible outcomes will be 1,594,323.

## How many possible outcomes are there in 15 football matches?

This number can only take the values 0, 1, 2, … , 15, and each of these is different. Therefore there are 16 possible outcomes.

## How many possible outcomes are there of 13 football matches?

How many bet outcomes are possible in 13 different football matches? – Quora. Or the draw. And the total different possible outcomes will be 1,594,323.

## How many possible outcomes are there in 16 football matches?

By doing some simple math: 16 games in a week times 16 games equals 256 games and therefore 256 possible outcomes, excluding ties.

## How many combinations of 3 outcomes are there?

So 3 * 3 = 9 possibilities. Similarly for 3 matches it would be, 3*3*3 = 27 possibilities.

## How many possible outcomes for the individual games are there such that overall player A ends up with 3 wins 2 draws and 2 losses?

How many possible outcomes for the individual games are there, such that overall player A ends up with 3 wins, 2 draws, and 2 losses? Out of the 7 games player A can win any of the 3 games, which gives (73) possibilities.

## How many combinations of 4 items have no repeats?

The number of possible combinations with 4 numbers without repetition is 15.

## How many ways can you generate a team of 4 from 8 players?

The number of ways as requested = 7*5*1 = 35. The above determination ensures that each member of a 4 person group from among 8 people is distinct from the other.

## How do you calculate 4 number combinations?

The number of permutations of n objects taken r at a time is determined by the following formula: P(n,r)=n! (n−r)! A code have 4 digits in a specific order, the digits are between 0-9.

## What is the permutation of 4?

That is, to each of those 4 ways there correspond 3. Therefore, there are 4· 3 or 12 possible ways to choose two letters from four. ab means that a was chosen first and b second; ba means that b was chosen first and a second; and so on. Thus the number of permutations of 4 different things taken 4 at a time is 4!.

## How do you calculate all possible outcomes?

To find the total number of outcomes for two or more events, multiply the number of outcomes for each event together. This is called the product rule for counting because it involves multiplying to find a product.

## How many combinations of 8 teams are there?

So for 8 teams it will be 8C2 = 8*7*6!/(8–2)!* 2! = 28.

## How do you calculate the probability of a football match?

To get the percentage chance we divide each team’s individual score by the 30 matches. To get Fulham’s percentage you divide 14 by 30 = 46.66%. To get the Draw percentage you divide 10 by 30 = 33.33%. To get Aston Villa’s percentage you divide 6 by 30 = 20.00%.