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Basketball

How many ways can a basketball team of 3 players be chosen from 8 players?

In the end, we see that there are 84 ways to pick 3 people from a group of 9 as long as order does not matter. Consider another example.

Quick Answer, how many ways can a basketball team of 5 players be chosen from 8 player? We have to select 5 players from (8 – 1) = 7 players. ∴ The required number of ways is 21.

Moreover, how many ways are there to choose a 5 players basketball team out of 10 players without any position assignment )? There are 252 ways to select a committee of five members from a group of 10 people.

You asked, how many ways can 5 basketball players be chosen from a group of 9 players? 9-5!) = 126. Your final answer is 126 ways.

Best answer for this question, how many combinations of 3 options are there? 3*3*3=27 unique possibilities.

What is nCr formula?

In Maths, nPr and nCr are the probability functions that represent permutations and combinations. The formula to find nPr and nCr is: nPr = n!/(n-r)! nCr = n!/[r!

How many ways can five basketball players be placed in three positions?

Hence, there are 5⋅4⋅3 ways to fill the positions.

How many ways can you pick a 5 player basketball team from 12 possible players?

12C2 = 792 ways the coach can choose a team of 5.

How many ways can a team of 5 players be chosen from a group of 15 students?

So, there are 3003 ways of picking 5 people from a group of 15.

How many ways can you pick a 5 player basketball team from 10 possible players?

Therefore, the answer will be in (1 * 1 * 56) = 56 ways.

How many ways can a coach select a starting team?

2C* 5C,* «C, Thus, the number of ways to select the starting line up is 2*10*6 = 120.

How many ways are there to choose a soccer team consisting of 3 forwards?

They’re all not combined. So there’s a total of 274 different ways.

How many ways can 5 basketball players?

The number of ways in which 5 basketball players can be selected from 8 basketball players is 8C5=56 8 C 5 = 56 . Using the product rule, the total number of ways in which both these selections can be made is 330∗56=18480 330 ∗ 56 = 18480 .

How many ways can five basketball players be listed in order in a program?

5 basketball players can be listed in order in a program in 120 ways.

How many ways can you select two teams of five players each from a group of ten players?

There are thus 2(94)=252 possible outcomes.

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